Question

The uncertainity in the momentum of a particle is 3.31×10-2 kgms-1 . The uncertainty in its position is​

Answer 1

Answer:

1.6×10^−33m

Explanation:

Δp= 3.31×10−2kg m sec−1

Since, Δp×ΔX=h/4π

ΔX= h/4π×∆p= 6.626×10^-33/4×3.14×3.31×10^-2

=1.6×10^−33m

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Answer 2

Answer:

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