Question

The uncertainity in the position of a bullet weighing 20 g is ± $10^{-4}$ m. Calculate the uncertainity in its velocity.

Answer 1

According to the Heisenberg's uncertainty principle

$\Delta x.\Delta p\quad \ge \quad \frac { h }{ 4\pi  }$

$h=planks\quad constant\quad =6.626\times { 10 }^{ -34 }J.{ s }^{ -1 }$

$m\Delta v=\frac { 10 }{ 1000\quad kg } \times \Delta v\times\Delta v={ 10 }^{ -4 }m$

Hence,

$\frac { 6.626\times{ 10 }^{ -34 }J.{ s }^{ -1 } }{ 3.14\times 4 }={ 10 }^{ -4 }m$

$\frac { 6.626\times { 10 }^{ -34 }J.{ s }^{ -1 } }{ 12.56 }={ 10 }^{ -4 }m=5.27\times { 10 }^{ -28 }m{ s }^{ -1 }$

Therefore, uncertainty of the velocity is $5.27 \times { 10 }^{ -28 }m{ s }^{ -1 }.$

Answer 2

Heya mate.....

THE UNCERTAINITY 5.27×10^-²³