Chemistry, asked by chandankumar19858, 1 year ago

The uncertainity in velocity of an electron present in the nucleus of diameter 10^-10 m hypothetically should be approximately

Answers

Answered by Anonymous
2
Hello,
here you can use the formula,
∆x ×∆p=h/4π
(Heisenberg's uncertainty principle)

∆v=h/4πm∆x
∆v=6.63×10^-34÷(10^-10×9.1×10^-31×4×3.14
∆v=0.058×10^-13
∆v=5.8×10^-15m/s

Hope that helps.
keep learning.
Similar questions