Question

the uncertainty in momentum of a particle is 7.97×10^-2 kg m/s. calculate the uncertainty in position (h-6.626×10^-34 kg m^2 kg m^2 /s​

Answer 1

Answer:

Correct option is

B

1.59×10

−33

m

According to uncertainty principle

Δx.Δp=>h/4π

Putting the values

Δx=

4×3.14×(3.3×10

−2

)

6.6×10

−34

Δx=1.59×10

−33

m