The unequal side of a triangle measures 24cm and its area is 60cm2.find the perimeter of the given triangle
amitsinghto36:
is it an isoceles
it seems to be
how u do this?i cant understand
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s=√a=a=24/2
60²=√s(s-a)(s-a)(s-24)
3600=144(a²-144)
a²=25+144
a²=169
a=13
so we get the side
and the perimeter is 50
60²=√s(s-a)(s-a)(s-24)
3600=144(a²-144)
a²=25+144
a²=169
a=13
so we get the side
and the perimeter is 50
how s=root a and root a =a please make us understand.
it is done by heron's formula
ok thax.
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