Question

the unequal sides of an isosceles triangle measures 24 cm and its area is 60 CM square find this perimeter of the triangle

Answer 1

PLZ MARK IT AS BRAINLIEST ANSWER AND DROP A ♥

Answer 2

Answer:

50 cm

Step-by-step explanation:

Let us draw a isosceles triangle ABC in which

AD = y

BC = 24

AB = AC = x

Apply Pythagoras theorem in triangle ADC,

$x=\sqrt{12^2+y^2}\\\\x=\sqrt{144+y^2}...(i)$

Now, area if triangle ABC is given by

$A=\frac{1}{2}\cdot24\cdot y\\\\60=12y\\\\y=5$

Substituting the value of y in (i)

$x=\sqrt{144+5^2}\\\\x=\sqrt{169}\\\\x=13$

Therefore, the perimeter of triangle is

AB + BC + AC

= x + 24 + x

= 13 + 24 + 13

= 50 cm