The unit cell length of sodium chloride crystal is 564 pm. What is its density?
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Answer:
2.165g/cm^3
Explanation:
4Nacl ------> 4Na+ + 4Cl-
therefore, Z=4
a=564pm
Na=6.022×10^23
total mass of Nacl = 22.99+34.34
= 58.5g/mol
d = Z×M / a^3×Na
= 4×58.5 / (564×10^-10)^3 × 6.022×10^23
by calculating this we get,
d=2.165g/cm^3
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