Question

the unit digit of a two digit number is 3 and seven times the sum of the digit is the number itself .find the number.

Answer 1

let the 2 digit no. be 10x+3

ATQ,

7(X+3)=10x+3

X=6

so the required no. is 63

Answer 2

Step-by-step explanation:

Unit of two digit number is 3

Let the tens digit number be x

The Number will be 10x + 3

Sum of two digit number = x + 3

According to the question now :

➳ 7(x + 3) = 10x + 3

➳ 7x + 21 = 10x + 3

➳ 21 - 3 = 10x - 7x

➳ 18 = 3x

➳ x = 18/3

➳ x = 6

Therefore, the tens digit number is 6.

Hence,

The required number = 10x + 3 = 10(6) + 3 = 63.