Question

The unit digit of a two digit number is three and 7 times the sum of its digits the number itself. Find the number.

Answer 1

Answer:

Step-by-step explanation:

given the two digit number a3 , where 10a + 3 = 7(a + 3), then

10a + 3 = 7a + 21

3a = 18

a = 6.

the number is 63.

Answer 2

Answer:

_Hҽყα_

Step-by-step explanation:

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Units digit of a two digit number = 3

Let the tens digit of the number be x.

Number = 10x + 3

Sum of the digits = (x + 3)

Given that 7 times the sum of the digits is the number itself.

⇒ 7(x + 3) = (10x + 3)

⇒ 7x + 21 = 10x + 3

⇒ 10x - 7x = 21 - 3

⇒ 3x = 18

⇒ x = 6.

Therefore, the digits in the tens place is 6 and the number is 63.

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