Question

the unit digit of a two number is 3 and 7 times the sum of the digit is the number itself find the number

Answer 1

Hi ,

let the ten's place digit = x

unit place digit = 3

the number = 10x + 3----( 1 )

sum of the digits = x + 3 ---( 2 )

according to the problem given ,

7 times of ( 2 ) = ( 1 )

7( x + 3 ) = 10x + 3

7x + 21 = 10x + 3

21 - 3 = 10x - 7x

18 = 3x

3x = 18

x = 18 / 3

x = 6

put x value in ( 1 )

Therefore ,

required number = 10x + 3

=( 10× 6) + 3

= 60 + 3

= 63

I hope this helps you.

:)

Answer 2

Answer:

Unit of two digit number is 3

Let the tens digit number be x

The Number will be 10x + 3

Sum of two digit number = x + 3

According to the question now :

➳ 7(x + 3) = 10x + 3

➳ 7x + 21 = 10x + 3

➳ 21 - 3 = 10x - 7x

➳ 18 = 3x

➳ x = 18/3

➳ x = 6

Therefore, the tens digit number is 6.

Hence,

The required number = 10x + 3 = 10(6) + 3 = 63.