Math, asked by piushanshukumar, 1 year ago

The unit digit of the two digit number exceeds its tens digit by 6 and the product of two digit is less by 12 from the number.Find the number.

Answers

Answered by bansalkhushi
24

Answer: 28 or 36


Step-by-step explanation:

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Let unit digit be y and tens digit be x

≈ Then the two-digit no. will be = 10x + y

≈ y-x =6(unit digit exceeds the tens digit by 6)

...........(i)

≈ product = xy

≈ (10x + y)-xy = 12 ( the product is less by 12 from the no.).

≈ 10x + y = 12 + xy ............(ii)


Solving (i) and (ii) simultaneously:

From (i) we get : y = 6 + x. ............(iii)

≈ putting the value of (iii) in (ii)

≈ {10x + (6 + x)} = 12 + x(6 + x)

≈ (10x + x + 6) = 12 + 6x + x^2

≈ 11x + 6 = x^2 + 6x + 12

≈ 5x = x^2 + 6

≈ Solving the equation, we get x= 2 or 3 Putting the value of x one by one for both values in (i)

If x = 2:

y - 2 = 6

≈ y = 8 ; then the no. would be 10*2 + 8

≈ 20 + 8

≈ 28....ANS

Or if x = 3:

y - 3 = 6

≈ y = 9 ; then the no. would be 10*3 + 6

≈ 30 + 6

≈ 36....ANS

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Hope it would help you. Plz give stars, it took a lot of tym to type this.

Answered by akhildeeptoppo
15

Answer:

8 OR 9

Step-by-step explanation:

Let digit in tens place = x

therefore, the digit in unit place be x+ 6

therefore, the number= ( x + 6 )+ 10x

= x+6+10x

= 11x + 6

product of two digit number= x(x+6)

= x2+6x

According to the question

→ x2 + 6x= ( 11x + 6 ) - 12

→ x2+6x=11x-6

→x2+6x-11x+6=0

→x2-5x+6=0

→x2-(3+2)x+6=0

→x2-3x-2x+6=0

→x(x-3) -2(x-3)=0

→(x-3) (x-2)=0

Therefore, Either, (x-3)=0

x=3

OR, (x-2)=0

x=2

Possible value for the digit unit place be

(i) Either, x+6=3+6=9

(ii)or, x+6=2+6=8

This is a correct answer

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