Question

the unit of pseudo first order reaction is

Answer 1

hi,

here is your answer,

Therefore, the order of reaction now becomes one, that is the reaction is now first order reaction. Such reactions are called pseudo-first order reactions. Another example of pseudo first-order reaction is the inversion of cane sugar.

Answer 2

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here is your answer

Consider a reaction in which one reactant is in excess, say hydrolysis of ethyl acetate. During the hydrolysis of 0.01 mol of ethyl acetate with 10 mol of water, the reaction goes like this,

CH3COOC2H5   + H2O     →   CH3COOH    +    C2H5OH

Time CH3COOC2H5 H2O CH3COOH C2H5OH

t = 0 0.01 mol 10 mol o mol 0 mol

t 0 mol 9.9 mol 0.01 mol 0.01 mol

As the concentration of water does not get altered much during the process ( because it is in excess), we can take it as constant. So in the rate equation, Rate = k′ [CH3COOC2H5] [H2O]  the term [H2O] can be taken constant. Thus, the equation becomes

Rate =  k [CH3COOC2H5] where k = k′[H2O]

Therefore, the order of reaction now becomes one, that is the reaction is now first order reaction. Such reactions are called pseudo-first order reactions.

Another example of pseudo first-order reaction is the inversion of cane sugar.

C12H22O11     +      H2O     →       C6H12O6      +      C6H12O6

Cane sugar                                    Glucose                Fructose

Rate = k[C12H22O11]

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