Question

The unit place digit of H.C.F. of 2^2 x 3^2 x 5^3 x 7, 2^3 x 3^3 x 5^2 x 7^2 and 3 x 5 x 7 x 11 is​

Answer 1

Explanation:

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Answer 2

Answer:

The HCF is 105.

Explanation:

As per the data given in the question,

We know that,

HCF is the product of lower powers of common factors.

So, we have

$a) \:2^{2}\times 3^{2}\times 5^{3} \times 7 \\b) \:2^{3}\times 3^{3}\times 5^{2}\times 7^{2}\\c) \: 3\times5\times7\times11$

So, here common factors are 3,5,7

and lowest power is 1 for each.

So, HCF is $3\times5\times7$ = 105

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