Question

The unit vector along i+j is

Answer 1

Explanation:

Unit vector along (i+j) is (i+j)/|i+j|

|i+j| is magnitude of (i+j)

we know,

i and j are perpendicular to each other

so, |i+j| = √i^2+j^2+2ijcos90°

√1+1 = √2

hence, unit vector along (i+j) is (i+j)/√2