Physics, asked by ankita123kumari, 1 year ago

The unit vector along icap +jcap

Answers

Answered by abhi178
378
unit vector along ( i + j) is ( i + j)/| i + j|
|i + j | is magnitude of ( i + j)
we know,
i and j are perpendicular to each other
So, |i + j| = √(i² + j² + 2.I.j.cos90°)
= √( 1 + 1) = √2
hence, unit vector along (i + j) is (i + j)/√2
Answered by Twinkle007
77

Answer:

unit vector along ( i + j) is ( i + j)/| i + j|

|i + j | is magnitude of ( i + j)

we know,

i and j are perpendicular to each other

So, |i + j| = √(i² + j² + 2.I.j.cos90°)

= √( 1 + 1) = √2

hence, unit vector along (i + j) is (i + j)/√2

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Explanation:

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