Question

The units digit of a 2-digit number is 3 and 7 times the sum of the digits is the number itself. Find the number.

Answer 1

Answer:

63

Step-by-step explanation:

Let the number be 10x+y

y= 3

7(x+y) = 10x + y

7x + 7y = 10x + y

7x + 21 = 10x + 3

21 - 3 = 10x - 7x

I.e. 3x = 18

x = 6

I.e. required number = 10x + y

= 10 × 6 + 3

= 60 + 3

= 63

Answer 2

Answer:

Unit of two digit number is 3

Let the tens digit number be x

The Number will be 10x + 3

Sum of two digit number = x + 3

According to the question now :

➳ 7(x + 3) = 10x + 3

➳ 7x + 21 = 10x + 3

➳ 21 - 3 = 10x - 7x

➳ 18 = 3x

➳ x = 18/3

➳ x = 6

Therefore, the tens digit number is 6.

Hence,

The required number = 10x + 3 = 10(6) + 3 = 63.