Question

The units digit of a two-digit number is 3 and seven times the sum of the digits is the number itself. Find the number.​

Answer 1

Answer:

63

Step-by-step explanation:

Any two digit no. = 10x+y

(x+y)7=10x+y

y=3

(x+3)7=10x+3

21-3=10x-7x

18=3x

Thus x=6

The number is (10X6)+3 = 63

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Answer 2

Answer:

63

Given:

Unit's digit of a two number digit is 3 and seven times the sum of the digits is the number itself

To find:

The number

Solution:-

Let ten's digit be 10x and unit's digit be y

Unit digit=3

i.e;y=3

Now

According to question

10x+y=7(x+y)

10x+3=7(x+3)

10x+3=7x+21

10x-7x=21-3

3x=18

x=18/3

x=6

------------------------

The number=10x+y

=10×6+3

=60+3

=63