x²- 28x +192=0 ,find the value of x ?
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x^2 - 28 x +192
=x^-(12+16)x +192, since 12 *16 =192 and 12 + 16 = 28 .
=x^2-12x-16x+192
=x(x-12) -16(x-12)
=(x-16) (x-12)
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