Math, asked by vaj, 1 year ago

the units digit of a two-digit number is 3 and seven times the sum of the digits is the number itself. find the number.

Answers

Answered by mousumi6
1
is the the no. is 63

vaj: how
mousumi6: is it correct or not??
vaj: yup correct
mousumi6: ok
mousumi6: so let the tens place digit be x........ then according to question..... 7(x+3) = 10x +3 ......7x + 21 = 10x + 3..... 3x = 18......x = 6....so the no. is 63
vaj: thanks
mousumi6: ur most welcome
Answered by Anonymous
1

Answer:

Unit of two digit number is 3

Let the tens digit number be x

The Number will be 10x + 3

Sum of two digit number = x + 3

According to the question now :

➳ 7(x + 3) = 10x + 3

➳ 7x + 21 = 10x + 3

➳ 21 - 3 = 10x - 7x

➳ 18 = 3x

➳ x = 18/3

➳ x = 6

Therefore, the tens digit number is 6.

Hence,

The required number = 10x + 3 = 10(6) + 3 = 63.

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