Question

the units digit of a two digit number is 3 and seven times the sum of the digit is the number itself .find the number

Answer 1

Yo,
Nice Questions! ♥

Let's unlock the answers now…

==============================================
Units digit of a two digit number = 3
Let the tens digit of the number be x.
Number = 10x + 3
Sum of the digits = (x + 3)

Given that 7 times the sum of the digits is the number itself.

⇒ 7(x + 3) = (10x + 3)

⇒ 7x + 21 = 10x + 3

⇒ 10x - 7x = 21 - 3

⇒ 3x = 18

⇒ x = 6.

Therefore, the digits in the tens place is 6 and the number is 63.

==============================================

Hope my answer helped … ☺ :)) :P

Answer 2

Hey...!!!

_______________
_______________

Unit digit of a two digit no = 3

Let digit at tens place be x

Two digit No. = 10 × tens place + 1 × ones place

 . = 10x+3

7(x + 3) =10x + 3

7x + 21 = 10x+3

21-3 = 10x-7x

x=18/3

x=6

Two digit no = 10 × 6+3

  =  60+3

  = 63 Ans.
_________________
_________________

I Hope It's help you....!!!!