Question

the upper boundary of class interval 10-19 among the following intervals 0-9 10-19 20-29 30-39​

Answer 1

Answer:

10−19,20−29,30−39,...

Here the class intervals are not continuous. To make them continuous take the mean of upper limit of first class and lower limit of second class.

Mean =

2

19+20

=19.5, which gives the upper limit of first class and lower limit of second class for the continuous class intervals.

Answer 2

Answer:

10-19

Step-by-step explanation:

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