The upper half of an inclined plane with inclination phi is perfectly smooth while the lower half is rough. A body starting from rest at the top will again come to rest at the bottom if the coefficient of friction for the lower half is given by
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Answer:
Suppose the length of the plane is L. When block descends the plane, rise in kinetic energy = fall in potential energy = mgLsinθi
Work done by friction = μ × (reaction) × distance 0 + μ(mgcosθ) × (L/2)
= μ(mgcosθ) × (L/2)
Now, work done = change in KE
mgLsinθ = μ(mgcosθ) × (L/2)
⇒tanθ = μ/2
∴μ = 2tanθ.
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