The upper part of a pole broken over by the wind makes an angle of 30 degree with and the distance from the root to the point where the top of the tree touches the ground is 10m : what was the height of the original tree?
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I am assuming that the question has been mistyped. I am answering the question as per the the question below:
The upper part of a pole broken over by the wind makes an angle of 30 degree with the ground and the distance from the root to the point where the top of the pole touches the ground is 10m. What was the height of the original tree?
Answer: This makes a triangle with the base = 10m, and we need to calculate the height and the hypotenuse. The height can be obtained using the formula tan30 = (height/base) which will give you the height = 5.77m.
Similarly the Hypotenuse can be calculated using the formula cos30 = 10/(Hypotenuse) which will give you the Hypotenuse = 11.54m.
Adding the height and hypotenuse will give you = 17.32m which is your answer.
The upper part of a pole broken over by the wind makes an angle of 30 degree with the ground and the distance from the root to the point where the top of the pole touches the ground is 10m. What was the height of the original tree?
Answer: This makes a triangle with the base = 10m, and we need to calculate the height and the hypotenuse. The height can be obtained using the formula tan30 = (height/base) which will give you the height = 5.77m.
Similarly the Hypotenuse can be calculated using the formula cos30 = 10/(Hypotenuse) which will give you the Hypotenuse = 11.54m.
Adding the height and hypotenuse will give you = 17.32m which is your answer.
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