Question

The upper part of a tree broken due to wind makes ∠60° with the level ground. If the distance

between base and upper part of the tree touching the ground is 10 m , find the total height of

the tree ​

Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

• AC be the the height of tree h

• AB is heart Brocken tree

• BD is fallen down tree making angle 60° with ground.

• heart Brocken tree = fallen down on ground AB = BD.. 1

now,

cos60° = BC/BD

1/2 = BC/ 10

2BC = 10

BC = 5m ...2

but AC = AB + BC

AC = 10 + 5 ...from 1 and 2

AC = 15 m

Height of three = 15 m