Math, asked by jagdishjambe7204, 9 months ago

The upper quartile 12,5,22,30,7,36,14,42,15,53,25,65 is

Answers

Answered by kishoreravi415
0

Answer:mnbvc754322f7876551234567890098765432112345678900564534867435687343674gcbchnfc5g4n67g76ngccggg3dh7d6887h78g8767bcb4b6g4h4d

Step-by-step explanation:

Answered by NainaRamroop
0

Given:

The set of numbers: 12,5,22,30,7,36,14,42,15,53,25,65

To Find:

The Upper Quartile (U.Q)

Solution:

To solve this question follow the steps given below,

  • We must first arrange the numbers in ascending order:

        5, 7, 12, 14, 15, 22, 25, 30, 36, 42, 53, 65

  • Count the total amount of numbers in the set. (referred to as n)

        n= 12

  • Use the formula given below to find the term where the U.Q is placed after arrangement.
  • Formula to find the term of U.Q =

        \frac{3}{4} * (n +1)

Given,

n=12

Solve,

= \frac{3}{4} * (12+1) \\\\ = \frac{3}{4} * 13

= \frac{39}{4}

= 9.75

The 9.75th term in the set is the U.Q

As 9.75 is not a whole number use the average of the 9th and 10th term to find U.Q

9th term = 36

10th term= 42

Upper Quartile= \frac{36 + 42}{2}

                        = 39

Hence, the Upper Quartile of 12,5,22,30,7,36,14,42,15,53,25,65 is 39.

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