Question

The upthrust force on an object equals 250N. What is the weight of the displaced water?​

Answer 1

Answer:

250N IS THE ANSWER.

Explanation:

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Answer 2

Answer:

The weight of the displaced water is 25.5 Kg.

Explanation:

Archimede's principle states that the weight of the water displaced by an object, which is fully or partially immersed in a fluid is equal to the force of buoyancy acting on the object.

Buoyancy is the upthrust acting on an object in a fluid. Here it is given that the upthrust on the object is 250 N. So the buoyancy is 250 N. Then the weight of the water displaced by the object will be 250 N = 25.5 Kg (∵ 1N = 0.10197 Kg).