Question

The v.D of a mixture contains no2 and n2o4 is 38.3 at 27c.Moles of no2 in 100g of mixture are

Answer 1

Answer:

Explanation:

Solubility is the maximum amount of a substance that will dissolve in a given amount of solvent at a specific temperature. There are two direct factors that affect solubility: temperature and pressure. Temperature affects the solubility of both solids and gases, but pressure only affects the solubility of gases.

Answer 2

Answer:

Solution:-

$.$

The vapour density of a mixture containing NO2 and N2O4 is 38.3 at 27°C. Calculate the mole of NO2 in 100 gram of mixture?

Let the total number of moles = 1

let the number of moles of NO2 = X

so number of moles of N2O4 = 1 -x

molar mass of mixture = 2 x vapour density

= 2 × 38.3 = 76.6

Now x × 46 + ( 1-x) 92 = 76.6

46 x + 92 -92 X = 76.6

46 x = 15.4

x = 15.4 / 46 = 0.335

% age of NO2 = 33.5 %

% age of N2O4 = 66.5 %

Number of moles NO2 in 100 g of mixture =0.335 × 100 / 76.6 = 0.437.

Hence, Solved!

_______________________________

Hope it helps you dear!