Question

the valency of Cr in the complex [Cr(H2O)4Cl2]+ is a) 1 b) 3c) 5 d) 6 please answer my question fast

Answer 1

In this complex structure, then valency of Cr will be 6.
Reasoning:
according to your question, its primary valency is +2, As H2O is a neutral molecule and Cl usually carries -1 charge.

So, in the given molecule, there are 2 Chloride ions and hence the charge (i.e., primary valency) of Cr is (+2).

On the other hand, there are four H20 molecules directly surrounds the central Cr(II) ion. Hence Secondary valency of Cr is 4.
Therefore, the valency will be = primary + secondary, i.e. 2+4=6

However, if you want the oxidation state of Cr here, then it will be +3.

Hope you understand. Thank you. ☺♥

Answer 2

Answer:

Explanation:

In this complex structure,the valency of Cr will be 6.

If you want the oxidation state (O.S) of Cr then it will be calculated as

[Cr (H2O)4Cl2]+

X +4×0 + (-2)= 1

X-2=1

X=1+2

X=3

Now For maximum Oxidation:-

The electronic configuration of Cr is

[Ar]3d54s1

Since it has 6e- in its valence shell,it can lose a maximum of 6 electrons.

Hence the maximum oxidation state of Cr is +6.

Thanks..