The value for equilibrium constant for forward reaction is 2.5, what will be the value for equilibrium constant for backward reaction?
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Correct option is A)
We have, Keq=kbkf, kf→ Rate constant of forward reaction
↙ kb→ rate constant of backward reaction
Equilibrium
constant
⇒kb=Keqkf=2.50.05×102=2550=2sec.
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