Question

the value in a certain system of measurement is 200units. if unit of mass is doubled the unit of length is trebled the unit of time is halved then the value of force in new system of units is x⅓ then the value of x is


needed step-by-step solution ​

Answer 1

Given:

The value in a certain system of measurement is 200units.

To find:

If unit of mass is doubled the unit of length is trebled the unit of time is halved then the value of force in new system of units is x⅓ then the value of x is

Solution:

From given, we have,

F = [MLT^{-2}]

The unit of mass is doubled the unit of length is trebled the unit of time is halved  

Let Fn represents the new force.

Fn =  [(2 × M) (3 × L) (T^{-2}/2)]

Fn = 3  [MLT^{-2}]

⇒ Fn = 3 F

If F = 200 units,

x = Fn = 3 × 200 = 600 units

then ∛x = ∛600 = 8.43 units

∴ x = 600 units , ∛x = 8.43 units

Answer 2

Answer:

the value in a certain system of measurement is 200units. if unit of mass is doubled the unit of length is trebled the unit of time is halved then the value of force in new system of units is x⅓ then the value of x is

Explanation:

x=600