Question

the value of 0.272bar+0.1363
63 Has bar

Answer 1

Answer:

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$x = \frac{23}{99} .....(1)$

$y = \frac{22}{99} .......(2)$

Therefore,

x+y

$= \frac{(23 + 22)}{99}$

$= \frac{45}{99}$

$= \frac{5}{11} </em><em>answer:</em><em>-</em><em>$

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Answer 2

The value of  $0.\overline{272}$ + $0.13\overline{63}$ = 0.41

Given:

$0.\overline{272}$ + $0.13\overline{63}$

To find:  

The value of  $0.\overline{272}$ + $0.13\overline{63}$

Solution:  

Given numbers are  $0.\overline{272}$  and  $0.13\overline{63}$  

To add given numbers convert them into fractions as given below

Let x = $0.\overline{272}$  

=> 1000x = 272.272272.....

=> 1000x - x = 272.272272..... - 0.272272...

999x = 272

x = 272/999    

=>  $0.\overline{272}$  = 272/999  

Let x =  $0.13\overline{63}$  

$0.13\overline{63}$  = (1363 - 13)/9900

$0.13\overline{63}$  = 1360/9900  

=>  $0.\overline{272}$ + $0.13\overline{63}$ = 272/999 + 1360/9900  

=>   450160/ 1098900 = 0.41  

Therefore,

The value of  $0.\overline{272}$ + $0.13\overline{63}$ = 0.41          

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