Math, asked by donkuparlynnong2, 5 hours ago

The value of 1+[1/(8×2)] + [1/(8×2^2) + [1/(8×2^3)] is​

Answers

Answered by pro10banerjee
1

Answer:

1 + ( \frac{1}{8 \times 2} ) + ( \frac{1}{8 \times  {2}^{2} }) + ( \frac{1}{8 \times  {2}^{3} } ) \\ 1 +  ( \frac{1}{16} ) + ( \frac{1}{32} ) + ( \frac{1}{64} ) \\  1 + ( \frac{4 + 2 + 1}{64} ) \\ 1 +  \frac{7}{64} \\  \frac{7 + 64}{64}  =  \frac{71}{64}

Step-by-step explanation:

If this helps mark me as the brainliest.

Answered by shlokramane2010
0

Answer:

Step-by-step explanation:

8 ×2

equals to 16

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