the value of 1/15+2/35+1/63+1/99+1/143 is _______
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[tex] \frac{1}{3*5} + \frac{1}{7*5} + \frac{1}{7*9} + \frac{1}{9*11} + \frac{1}{11*13}
= (\frac{1}{3} - \frac{1}{y13} )/2
= \frac{5}{39} [/tex]
reshma141:
what is the method you have used here?
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