Question

the value of
1+i/1-i​

Answer 1

i

1+i/1-i

firstly, we rationalising this term

1+i/1-i*1+i/1+i

it gives,

(1+i)^2/1^2-i^2

2i/2=i

Answer 2

Answer:

$i \: or \: \sqrt{ - 1}$

Step-by-step explanation:

$\frac{1 + i}{1 - i } \\ = \frac{1 + i}{1 - i } \times \frac{1 + i}{1 + i} \\ = \frac{ {(1 + i)}^{2} }{(1 - i)(1 + i)} \\ = \frac{1 + 2i + {i}^{2} }{1 - {i}^{2} } \\ = \frac{1 + 2i - 1}{1 + 1} \\ = \frac{2i}{2} = i = \sqrt{ - 1}$

i=√-1

i^2=-1

Mark brainliest