Question

The value of (1 - i)100 is
a) 2100(cos 100m - i sin 1007)
b) 2100 (cos 257 - i sin 257)
d) 250 (cos 100m - i sin 100m)
c) 250 (cos 2511 - i sin 251)​

Answer 1

Answer:

This implies that

x2+2ax=4x−4a−13

or

x2+2ax−4x+4a+13=0

or

x2+(2a−4)x+(4a+13)=0

Since the equation has just one solution instead of the usual two distinct solutions, then the two solutions must be same i.e. discriminant = 0.

Hence we get that

(2a−4)2=4⋅1⋅(4a+13)

or

4a2−16a+16=16a+52

or

4a2−32a−36=0

or

a2−8a−9=0

or

(a−9)(a+1)=0

So the values of a are −1 and 9.