the value of (1+i)power5.(1-i)power5 is
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I have a short cut for u
Therefore (a+b) (a-b) =a^2-b^2
& a=1^5 & b=i^5
So,
(1^5)^2 - (i^5)^2
1-i^2
1-(-1)
=1+1=2
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