Question

The value of 1+tan 5° cot 85° is equal

a) sin^2 5°
b) cos^2 5°
c) sec^2 5°
d) cosec^2 5°​

Answer 1

Answer:

Step-by-step explanation:

We have,

$\tt{1+tan(5^{\circ})\,cot(85^{\circ})}$

$\tt{=1+tan(5^{\circ})\,cot(90^{\circ}-5^{\circ})}$

$\tt{=1+tan(5^{\circ})\,tan(5^{\circ})}$

$\tt{=1+tan^2(5^{\circ})}$

$\tt{=sec^2(5^{\circ})}$

Answer 2

Answer:

Step-by-step explanation:

$\large{\mathtt{1+tan(5°)cot(85°)}}$

$\large{\mathtt{1+tan(5°)cot(90°-5°)}}$

$\large{\mathtt{1+tan(5°)tan(5°)}}$

$\large{\mathtt{1+tan^2(5°)}}$

$\large{\mathtt{\Rightarrow sec^2(5°)}}$