Question

The value of (1 + tan2A)(1 − sin A)(1+ sin A) is

Answer 1

Answer:

1

Step-by-step explanation:

(1+tan^2A)(1-sinA)(1+sinA)

= sec^2A(1-sin^2A)

= 1/cos^2Axxcos^2A

= 1

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Answer 2

Answer:

1

Step-by-step explanation:

(1+tan^2A) (1-sin A) (1+sin A)

=> sec^2A(1 - sin^2A)

=> 1/cos^2Axxcos^2A

= 1.

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