The value of(√11-√2)(√11-√2)
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(√11-√2)(√11-√2) = 13 - 2√22
Given:
(√11-√2)(√11-√2)
To find:
The value of(√11-√2)(√11-√2)
Solution:
We have been given (√11-√2)(√11-√2)
As we can see that both the brackets have same terms
The number is multiplied by itself, so we can put square on it
So, our question will be
(√11-√2)²
Now, we have the formula of (a-b)²
(a-b)² = a² + b² - 2ab
Now, a = √11
b = √2
We just have to apply the formula
(√11-√2)² = (√11)² + (√2)² - 2√11 √2
= 11 + 2 - 2√22
= 13 - 2√22
Hence, our answer will be 13 - 2√22.
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