Math, asked by tanishkatanawade, 6 months ago

The value of [2-3(2-3)^-1]^-1

Answers

Answered by malikakash1976
69

Answer:

It's just simple.

(2–3(2–3)^-1)^-1

=(2–3(—1)^-1)^-1

=(2–3(—1))^-1

=(2+3)^-1

=5^-1

=1/5

You just have to do it step by step.

Answered by rkbhukta93407
16

Answer:

It's just simple.

(2–3(2–3)^-1)^-1

=(2–3(—1)^-1)^-1

=(2–3(—1))^-1

=(2+3)^-1

=5^-1

=1/5

Step-by-step explanation:

The rule of BODMAS:

First solve the equation in the round brackets: (2–3) which is -1.

Now raise it by its power -1. -1^-1 is -1. Now you have <2–3(-1)>^-1.

Open the round bracket. <2+3>^-1

Open the brackets 5^-1.

Which is 1/5.

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