Math, asked by lovelyprem857, 6 months ago

The value of 2 sin2A + 4 sec2 A + 5 cot2 A + 2 cos2A – 4 tan2 A – 5

cosec2 A is [ ]

a) 0 b) 1 c) 2 d) 3​

Answers

Answered by Anonymous
2

Answer:

Step-by-step explanation:

2 sin²A + 4 sec² A + 5 cot² A + 2 cos²A – 4 tan² A – 5 cosec² A

=2 sin²A+2 cos²A +4 sec² A – 4 tan² A + 5 cot² A   – 5 cosec² A

=2( sin²A+ cos²A) +4 (sec² A –  tan² A) + 5( cot² A   – cosec² A)

=2*1+4*1+5*-1

=2+4-5

=1

ans (b) 1

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