The value of 2 sin2A + 4 sec2 A + 5 cot2 A + 2 cos2A – 4 tan2 A – 5
cosec2 A is [ ]
a) 0 b) 1 c) 2 d) 3
Answers
Answered by
2
Answer:
Step-by-step explanation:
2 sin²A + 4 sec² A + 5 cot² A + 2 cos²A – 4 tan² A – 5 cosec² A
=2 sin²A+2 cos²A +4 sec² A – 4 tan² A + 5 cot² A – 5 cosec² A
=2( sin²A+ cos²A) +4 (sec² A – tan² A) + 5( cot² A – cosec² A)
=2*1+4*1+5*-1
=2+4-5
=1
ans (b) 1
Similar questions