Question

The value of (27^1/3+64^1/3)^2

Answer 1

Answer:

(27⅓+64⅓)²=((3×3×3)⅓+(4×4×4)⅓)²=(3+4)²=7²=49; Please mark the answer as brainliest.

Answer 2

The value of the expression is 49.

Given:

The given expression is

${( {64}^{ \frac{1}{3} } + {27}^{ \frac{1}{ 3} } )}^{2}$

To find:

The value of the expression.

Solution:

To determine the value of the expression we have to follow the below steps as follows-

The given expression is

${( {64}^{ \frac{1}{3} } + {27}^{ \frac{1}{ 3} } )}^{2}$

We know that 64 is a cube of 4 and 27 is a cube of 3.

So, we can write-

${( { {4}^{3} }^{ \frac{1}{3} } + { {3}^{3} }^{ \frac{1}{ 3} } )}^{2} \\ {(4 + 3)}^{2} \\ = {7}^{2} \\ = 49$

The value of the expression is 49.

#SPJ3