Question

the value of 2sin^2 a +4sec^2a+5cot^2a +2 cos^2a -4tan^2a-5 cosec^2 a​

Answer 1

Answer:

Given, cosθ=

13

5

Then sinθ=

13

12

Hence, tanθ=

5

12

and

cosecθ=

12

13

Substituting in the equation, we get

=

12

13

−

13

5

13

5

+

12

5.5

=

13(13)−5(12)

5(12)+25(13)

=

169−60

60+300+25

=

109

385