Question

The value of 3(243)⁻¹/⁵ + 6²(216)⁻²/³ is

Answer 1

Step-by-step explanation:

3 (243) ^ (-/1/5) + 6²(216)^(-2/3)

3(3×3×3×3×3)^(-1/5) +6²(6×6×6)^(-2/3)

3((3)^5^)(-1/5)+6²((6)^3))^(-2/3)

3(3)^5×-1/5+6²(6)^3×(-2/3)

3×(3)^(-1)+6²(6)^(-2)

3×1/3+6²×(1/6)^2

1+6²×1/36

1+36×1/36

1+1

2