The value of 4 and 5 if a&b=ab²
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Step-by-step explanation:
=ab(a+b)
Given,
a=1/(3–2√2)
b=1/(3+2√2)
Now,
ab= 1/(3–2√2)×1/(3+2√2) = 1/{(3)²-(2√2)²}
= 1/(9–8) = 1
a+b = 1/(3–2√2)+1/(3+2√2)
= (3+2√2+3–2√2)/{(3)²-(2√2)²} = 6/(9–8) = 6/1
= 6
Therefore, a²b+ab² = ab(a+b) = 1/6 [Ans].
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