Question

The value of 4(x)^3 y^3 z^3 ÷2xy​

Answer 1

Step-by-step explanation:

x+y+z=0

$x ^{3} + {y}^{3} + {z}^{3} = 3xyz$

$x ^{3} + {y}^{3} + z ^{3} - 2xyz = xyz$

$( \sqrt{7} - \sqrt{5} )( \sqrt{5} - \sqrt{3} )( \sqrt{3} - \sqrt{7} )$

$( \sqrt{7} - \sqrt{5} )( \sqrt{15} - \sqrt{35} - 3 + \sqrt{21} )$

$2 \sqrt{7} + 2 \sqrt{3} - 4 \sqrt{5}$

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