Question

the value of 4sinA cos^3A - 4 cosA sin ^3A​

Answer 1

Step-by-step explanation:

Let us consider the problem:

LHS=sin4A

RHS=4sinAcos

3

A−4sin

3

AcosA

Let the consider L.H.S =sin4A

⇒ 2sin2Acos2A

⇒ 2[2sinAcos2A][cos

2

A−sin2A]

⇒ 4[sincos

3

A−sin

3

AcosA]

=RHS

Answer 2

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Step-by-step explanation:

No error,

Answer clear ☑️