Question

The value of
(√6-√10-√21-√35)

Answer 1

If you are not able to understand ask in the comment section.

Answer 2

The value of expression is $(\sqrt6-\sqrt{10}-\sqrt{21}-\sqrt{35})=(\sqrt2-\sqrt{7})(\sqrt3-\sqrt5)$

Step-by-step explanation:

Given : Expression $(\sqrt6-\sqrt{10}-\sqrt{21}-\sqrt{35})$

To find : The value of expression ?

Solution :

Expression $(\sqrt6-\sqrt{10}-\sqrt{21}-\sqrt{35})$

Writing the square root in their multiple form,

$=((\sqrt2\times \sqrt3)-(\sqrt2\times \sqrt5)-(\sqrt3\times \sqrt7)-(\sqrt5\times \sqrt7))$

$=(\sqrt2(\sqrt3-\sqrt5)-\sqrt7(\sqrt3-\sqrt5)$

$=(\sqrt2-\sqrt{7})(\sqrt3-\sqrt5)$

Therefore, the value of expression is $(\sqrt6-\sqrt{10}-\sqrt{21}-\sqrt{35})=(\sqrt2-\sqrt{7})(\sqrt3-\sqrt5)$

#Learn more

(7+3 sqrt5) ( 7 - 3 sqrt5)​

https://brainly.in/question/11504363