Math, asked by chandrabhushan5, 1 year ago

the value of (6√27-√27/4)^2=

Answers

Answered by 112JAI
9
(6√27-√27/4)²=(6√27)²+(√27/4)²-2*6√27*√27/4
                      =(36*27)+(27/16)-12*27/16
                      =972+1.6875-20.25
                      =953.4375
Answered by vinitadevpal
13
6√27-√27/4)^2
by using identity (a-b)^2= a^2-2ab+b^2
here a=6√27 and b= √27/4
(6√27)^2 - 2×6√27×√27/4 + (√27/4)^2
972-81+1.6875
= 892.67 ans.

vinitadevpal: please mark as brainlist
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