Question

the value of √6+√6+√6+................. is

Answer 1

i think u mean this...
$\sqrt{6 + \sqrt{6 + \sqrt{6 + \sqrt{6 + .......} } } } = x......(i)$
well u can easily find it out...
squaring both sides....
x^2=6+√6+(√6+(√6+......)....(ii)

(ii)-(i)
x^2=6 + √6+(√6+....
x =. √6+(√6+.....
-------------------------------
x^2- x= 6
x^2-x-6=0
x^2-3x+2x-6=0
x(x-3) + 2(x-3)=0
(x-3)(x+2)=0
thus,
x=3 or x=-2

Hope it helps u...
if yes, mark brainliest...
Have a gr8 day ahead...

@TeraBhalaHo